5月20
jquery和prototype并存及冲突解决
<script type=”text/javascript”>
jQuery.noConflict();
</script>
上面是之前网上说的不行,下面这个方法可以,注意一定要按照这个顺序来
<script language = "JavaScript" src="jquery-v1.3.2.js" type = "text/javascript"></script><!--JQuery-->
<script type="text/javascript">var jQuery=$;</script>
<script language = "JavaScript" src="prototype.js" type = "text/javascript"></script>
<script>
function ajaxload(objid){
jQuery.ajax({
cache: "False",
type: "post",
url: "loaddata.asp",
data: "",
success: function(msg){
jQuery("#"+objid).html(msg);
},
error: function(){
}
});
}
</script>
最后编辑: tommyhu 编辑于2011/05/20 09:27
jQuery.noConflict();
</script>
上面是之前网上说的不行,下面这个方法可以,注意一定要按照这个顺序来
<script language = "JavaScript" src="jquery-v1.3.2.js" type = "text/javascript"></script><!--JQuery-->
<script type="text/javascript">var jQuery=$;</script>
<script language = "JavaScript" src="prototype.js" type = "text/javascript"></script>
<script>
function ajaxload(objid){
jQuery.ajax({
cache: "False",
type: "post",
url: "loaddata.asp",
data: "",
success: function(msg){
jQuery("#"+objid).html(msg);
},
error: function(){
}
});
}
</script>
最后编辑: tommyhu 编辑于2011/05/20 09:27
tommyhuc.cn网友
2011/05/20 11:24
很不错,谢谢楼主指点!
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